-mas = []
for N in range(1, 10000):
nBin = bin(N)[2::]
if N % 3 == 0:
nBin = '10' + nBin[2::] + '1'
else:
nBin = bin((N % 3) * 2)[2::] + nBin
#print (nBin)
R = int(nBin, 2)
if R > 8000:
mas.append(R)
print(sorted(mas))